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  • Maximum acceleration of block A after its collision with block B as shown in figure has magnitude (assume collision to be elastic, both blocks are of mass m) <img alt="" src="https://cdn.

Maximum acceleration of block A after its collision with block B as shown in figure has magnitude (assume collision to be elastic, both blocks are of mass m)

Option: 1

\sqrt{\frac{k}{m}}v


Option: 2

\sqrt{\frac{m}{k}}v


Option: 3

\frac{m}{k}v

 


Option: 4

\frac{k}{m}v


Answers (1)

best_answer

Answer (1)

\frac{1}{2}kx^{2}=\frac{1}{2}mv^{2}\Rightarrow x=\sqrt{\frac{m}{k}}v

\therefore f=kx=\sqrt{\frac{m}{k}}\times v \times k

\therefore a=\frac{f}{m}=\sqrt{m}\times v \frac{\sqrt{k}}{m}=v\sqrt{\frac{k}{m}}

 

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