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The equilibrium constants of the following are:

$\begin{array}{{20}c} {\text{N}_2 + 3\text{H}_2 \rightleftharpoons 2\text{NH}_3 } & {\text{K}_1 } \\ \end{array}$

$\begin{array}{{20}c} {\text{N}_2 + \text{O}_2 \rightleftharpoons 2\text{NO}} & {\text{K}_2 } \\ \end{array}$

$\begin{array}{*{20}c} {\text{H}_2 + \frac{1} {2}\text{O}_2 \to \text{H}_2 \text{O}} & {\text{K}_3 } \\ \end{array}$

The equilibrium constant (K) of the reaction:

$2\text{NH}_3 + {\raise0.7ex\hbox{5} \!\mathord{\left/ {\vphantom {5 2}}\right.\kern-\nulldelimiterspace} \!\lower0.7ex\hbox{2}}\text{O}_2 \mathop \rightleftharpoons \limits^\text{K} 2\text{NO} + 3\text{H}_2 \text{O}$

Option 1)
$K_1 {{K_3^3 } \mathord{\left/ {\vphantom {{K_3^3 } {K_2 }}} \right. \kern-\nulldelimiterspace} {K_2 }}$

Option 2)
$K_2 {{K_3^3 } \mathord{\left/ {\vphantom {{K_3^3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Option 3)
$K_2 {{K_3 } \mathord{\left/ {\vphantom {{K_3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Option 4)
$K_2^3 {{K_3 } \mathord{\left/ {\vphantom {{K_3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Answers (1)

best_answer

Equilibrium constant for the reverse reaction -

Equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction.

- wherein

$K'_{c}=\frac{1}{K_{c}}$

${K'_{c}}$ is equilibrium constant for reverse direction.

$N_{2}+3 H_{2}\rightleftharpoons 2NH_{3}, K_{1}$

$2 H_{3}\rightleftharpoons 3H_{2}+N_{2}}$ , $\frac{1}{K_{1}}$ - - - - - - - -- (1)

$H_{2}+\frac{1}{2}O_{2}\rightarrow H_{2}O , K_{3}$ - - - - -- - - - - -(2)

$3H_{2}+\frac{3}{2}O_{2}\rightarrow 3H_{2}O , K_{3}^{3}$ - - - - - - - - - - (3)

adding (1) (2) (3)

$3H_{2}+\frac{3}{2}O_{2}\rightleftharpoons 3H_{2}O , K=\frac{K_{2}K_{3}^{3}}{K_{1}}$

Option 1)

$K_1 {{K_3^3 } \mathord{\left/ {\vphantom {{K_3^3 } {K_2 }}} \right. \kern-\nulldelimiterspace} {K_2 }}$

Incorrect option

Option 2)

$K_2 {{K_3^3 } \mathord{\left/ {\vphantom {{K_3^3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Correct option

Option 3)

$K_2 {{K_3 } \mathord{\left/ {\vphantom {{K_3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Incorrect option

Option 4)

$K_2^3 {{K_3 } \mathord{\left/ {\vphantom {{K_3 } {K_1 }}} \right. \kern-\nulldelimiterspace} {K_1 }}$

Incorrect option

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divya.saini

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