Q

# Need explanation for: A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floo

A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floor will be:

• Option 1)

9.9m

• Option 2)

10.1m

• Option 3)

10m

• Option 4)

20m

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As learnt in

Tips of distance -

Distance is a scalar quantity.

It is always positive.

S.I. Unit $\rightarrow$ meter (m).

Dimension $\left [ L \right ]$

Distance is depend on path followed by body .

$Distance \geqslant Displacement.$

- wherein

Displacement along circle is zero(0).

Semi circle

$Distance=\pi r$

$Displacement =2\, r$

$F_{ext}= 0$     momentum remains conserved

$\therefore 50u +0.5\times 2 = 0$

where u - initial velocity of man

$u = -\frac{1}{50}ms^{-1}$     (negative sign shows that man moves upward)

Time taken by the stone

$t = \frac{10}{2} = 5\ sec$

$\therefore$  Distance moved by the man = $5 \times \frac{1}{50} = 0.1\ mt$

$\therefore$   Distance of the man above floor = 10 + 0.1 = 10.1 mt

Option 1)

9.9m

This option is incorrect

Option 2)

10.1m

This option is correct

Option 3)

10m

This option is incorrect

Option 4)

20m

This option is incorrect

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