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Need explanation for: A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floo

A man of 50 kg mass is standing in a gravity free space at a height of 10m above the floor. He throws a stone of 0.5kg mass downwards with a speed of 2m/s. When the stone reaches the floor, the distance of the man above the floor will be:

  • Option 1)

    9.9m

  • Option 2)

    10.1m

  • Option 3)

    10m

  • Option 4)

    20m

 
Answers (1)
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As learnt in

Tips of distance -

Distance is a scalar quantity.

It is always positive.

S.I. Unit 
ightarrow meter (m).

Dimension left [ L 
ight ]

Distance is depend on path followed by body .

Distance geqslant Displacement.

- wherein

Displacement along circle is zero(0).

Semi circle

Distance=pi r

Displacement =2, r

 

 F_{ext}= 0     momentum remains conserved

\therefore 50u +0.5\times 2 = 0

where u - initial velocity of man

u = -\frac{1}{50}ms^{-1}     (negative sign shows that man moves upward)

Time taken by the stone

t = \frac{10}{2} = 5\ sec

\therefore  Distance moved by the man = 5 \times \frac{1}{50} = 0.1\ mt

\therefore   Distance of the man above floor = 10 + 0.1 = 10.1 mt


Option 1)

9.9m

This option is incorrect

Option 2)

10.1m

This option is correct

Option 3)

10m

This option is incorrect

Option 4)

20m

This option is incorrect

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