For the cell reaction

2Fe^{3+}(aq)+ 2I^{-}(aq) \rightarrow 2Fe^{2+}(aq) + I_2(aq)

E^0_{cell} = 0.24V at 298K. The standard Gibbs energy (\Delta_r G^0) of the cell reaction is:

[Given that Faraday constant F = 96500 C mol-1]

  • Option 1)

    -46.32 kJ mol-1

  • Option 2)

    -23.16 kJ mol-1

  • Option 3)

    46.32 kJ mol-1

  • Option 4)

    23.16 kJ mol-1

Answers (1)

We know that 

    \Delta G^0 = -nFE^0_{cell}

\Rightarrow \Delta G^0 = -2\times 96500\times 0.24

\Rightarrow \Delta G^0 = -46.32 kJ mol^{-1}

Option 1 is correct


Option 1)

-46.32 kJ mol-1

Option 2)

-23.16 kJ mol-1

Option 3)

46.32 kJ mol-1

Option 4)

23.16 kJ mol-1

Most Viewed Questions

Preparation Products

Knockout NEET 2024

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports,.

₹ 29999/- ₹ 24999/-
Buy Now
Knockout NEET 2025

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, 24x7 Doubt Chat Support,.

₹ 45000/-
Buy Now
Knockout NEET (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports.

₹ 7999/- ₹ 4999/-
Buy Now
Knockout NEET 2023 (One Month)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports.

₹ 13999/- ₹ 6999/-
Buy Now
Knockout NEET (Three Months Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 5999/- ₹ 4499/-
Buy Now
Boost your Preparation for NEET 2021 with Personlized Coaching
 
Exams
Articles
Questions