A 20 litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be :

(Given that : \text{SrCO}_\text{3} \text{(s)} \rightleftharpoons \text{SrO(s) + CO2(g), K}_\text{p} = 1.6\,\text{atm})

  • Option 1)

    5 litre

  • Option 2)

    10 litre

  • Option 3)

    4 litre

  • Option 4)

    2 litre

 

Answers (1)

As we learnt in concept

Relation between Kp and Kc -

K_{p}=K_{c}(RT)^{\bigtriangleup n}

while calculating the value of Kp , pressure should be expressed in bar.

1\:bar=10^{5}pa

- wherein

\bigtriangleup n = (number of moles of gaseous products) - (number of moles gaseous reaction)

 

 SrCO_{3}\rightleftharpoons SrO+CO_{2}(g),K_{p}=1.6\:atm\\ K_{p}=P_{co_{2}}\\ n_{co_{2}}=\frac{PV}{RT}=\frac{0.4}{0.082\times 400}=\frac{8}{R400}=\frac{1}{50R}

For max. Volume of container, let's assume that n=constant, then p=1.6 atm

V=\frac{nRT}{p}=\frac{1}{50}\times \frac{100}{0.4}=5L


Option 1)

5 litre

This option is correct 

Option 2)

10 litre

This option is incorrect 

Option 3)

4 litre

This option is incorrect 

Option 4)

2 litre

This option is incorrect 

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