Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Need explanation for: - Equilibrium - NEET

A 20 litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the containers is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be :

(Given that : \text{SrCO}_\text{3} \text{(s)} \rightleftharpoons \text{SrO(s) + CO2(g), K}_\text{p} = 1.6\,\text{atm})

  • Option 1)

    5 litre

  • Option 2)

    10 litre

  • Option 3)

    4 litre

  • Option 4)

    2 litre

 

Answers (1)

best_answer

As we learnt in concept

Relation between Kp and Kc -

K_{p}=K_{c}(RT)^{\bigtriangleup n}

while calculating the value of Kp , pressure should be expressed in bar.

1\:bar=10^{5}pa

- wherein

\bigtriangleup n = (number of moles of gaseous products) - (number of moles gaseous reaction)

 

 SrCO_{3}\rightleftharpoons SrO+CO_{2}(g),K_{p}=1.6\:atm\\ K_{p}=P_{co_{2}}\\ n_{co_{2}}=\frac{PV}{RT}=\frac{0.4}{0.082\times 400}=\frac{8}{R400}=\frac{1}{50R}

For max. Volume of container, let's assume that n=constant, then p=1.6 atm

V=\frac{nRT}{p}=\frac{1}{50}\times \frac{100}{0.4}=5L


Option 1)

5 litre

This option is correct 

Option 2)

10 litre

This option is incorrect 

Option 3)

4 litre

This option is incorrect 

Option 4)

2 litre

This option is incorrect 

Posted by

Aadil

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2024 application correction facility ends today; exam pattern, marking scheme
anam-khan

NTA re-opens NEET UG correction window 2024; update photographs till April 26
anam-khan

NEET UG 2024 exam city slip out at neet.ntaonline.in; over 25 lakh candidates to appear

Latest Question