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  • Need explanation for: The hybridization involved in complex [Ni(CN)4]2-is: (At. No.Ni = 28)

The hybridization involved in complex [Ni(CN)4]2-is:     (At. No.Ni = 28)

  • Option 1)

    dsp2

  • Option 2)

    sp3

  • Option 3)

    d2sp2

  • Option 4)

    d2sp3

 

Answers (1)

best_answer

As we discused

Hybridisation -

sp3d2 - square bipyramidal or octahedral 

d2sp3 - octahedral 

sp3 - tetradedral 

dsp2 - square planar

- wherein

sp3d2 - outer complex

d2sp3 - inner complex

sp3 - [Ni(Cl)_{4}]^{2-}

dsp2 - [Pt(CN)_{4}]^{2-}

 

 In [Mi\left ( CN \right )_{4}]^{2-} The oxidation state of Mi is +2 and CN^{-} is a strong field ligand which can pain the unpaired electron of Ni^{2+}

 


Option 1)

dsp2

This is correct option

Option 2)

sp3

This is incorrect option

Option 3)

d2sp2

This is incorrect option

Option 4)

d2sp3

This is incorrect option

Posted by

Aadil

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