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  • Need explanation for: The solubility of BaSO4 in water is 2.42 x 10-3 gL-1 at 298 K. The value of its solubility product (Ksp) will be(Given molar mass of BaSO4 = 233 g mo1-1)

The solubility of BaSO4 in water is 2.42 x 10-3 gL-1 at 298 K. The value of its solubility product (Ksp) will be
(Given molar mass of BaSO4 = 233 g mo1-1)

 

  • Option 1)

    1.08 x 10-14 mol2 L-2

  • Option 2)

    1.08 x 10-12 mol2 L-2

  • Option 3)

    1.08 x 10-10 mol2 L-2

  • Option 4)

    1.08 x 10-8 mol2 L-2

 

Answers (1)

best_answer

As we learnt that

General expression of solubility product -

M_{x}X_{y}\rightleftharpoons xM^{p+}(aq)+yX^{2-}(aq)


(x.p^{+}=y.\bar{q})

- wherein

Its solubility product is 
 

K_{sp}=[M^{p+}]^{x}\:[X^{2-}]^{y}

 

 s = \frac{2.42 X 10^{-3}}{233} = 1.038 X 10^{-5} mole/L

K_{sp} =s^{2} = (1.038 X 10^{-5})^{2} = 1.08 X 10^{-10}

 


Option 1)

1.08 x 10-14 mol2 L-2

This is incorrect.

Option 2)

1.08 x 10-12 mol2 L-2

This is incorrect.

Option 3)

1.08 x 10-10 mol2 L-2

This is correct.

Option 4)

1.08 x 10-8 mol2 L-2

This is incorrect.

Posted by

Aadil

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