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16\:g of an ideal gas SO_{x} occupies 5.6\:L at STP. The value of x is 

Option: 1

2


Option: 2

3


Option: 3

5


Option: 4

1


Answers (1)

best_answer

 

Number of Moles of a gas at STP -

no of moles of a gas at STP = given volume of gas / 22.4 liter

-

 

1 mole of the gas at STP = 22.4L

5.6L at STP = 16g (given)

Thus, 22.4L at STP = (16 x 22.4)/5.6 
                             = 64g

Therefore, molecular mass off gas = 64g

Now, for SOx gas, we have:
=> 32 + 16x = 64
=> x = 2

Hence, gas is SO2

 

Posted by

Ajit Kumar Dubey

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