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One mole of an ideal gas expands from state X to Y by three paths 1, 2 and 3 as shown in the figure below. If W1, W2 and W3 are respective work done by ideal gas along the three paths then:

Option: 1

W_1 = W_2 =W_3


Option: 2

W_3>W_1>W_2


Option: 3

W_3>W_2>W_1

 


Option: 4

W_1>W_2>W_3


Answers (1)

best_answer

Work is a path function and not a state function. And Area under P-V curve gives Work done. As far as the magnitude is concerned, work done by gas will be maximum in path 3 because the area under the curve is highest in the case of path 3. The second highest area is under path 2 and the least area is of the curve 1.
Hence, Option number (3) is correct

Posted by

Sanket Gandhi

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