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One mole of an ideal gas initial state A undergoes a cyclic process ABCA, as shown in the figure. Its pressure at A is \mathrm{p_0}. Choose the correct option (s) from the following.

Option: 1

Internal energies at A and B are the same


Option: 2

\mathrm{\text { Work done by the gas in process } A B \text { is } p_0 V_0 \ln 4}


Option: 3

\mathrm{\text { Pressure at } \mathrm{C} \text { is } \frac{p_0}{4}}


Option: 4

Both a and b


Answers (1)

best_answer

\mathrm{\begin{aligned} & T_A=T_B \quad \therefore U_A=U_B \\ & W_{A B}=(1)(R) T_0 \ln \left(\frac{V_f}{V_i}\right) \\ & =R T_0 \ln \left(\frac{4 V_0}{V_0}\right) \\ & =p_0 V_0 \ln (4) \end{aligned}}

Information regarding p and T at C cannot be obtained from the given graph. Unless it is
mentioned that line BC passes through origin or not.
Hence, both (a) and (b) are the correct

Posted by

Deependra Verma

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