Get Answers to all your Questions

header-bg qa

Oxygen gas is kept in an open beaker at 2 atm pressure.
If the Pressure at surrounding sudden falls to 1 atm  and Temperature increase to 546 k, then the percentage at oxygen remains in boaters in Mn %. ot the inital Amount?

Option: 1

50 \%


Option: 2

25 \%


Option: 3

16 \%


Option: 4

16 \%


Answers (1)

best_answer

Let the intial mole of oxygen gas in the beater = n,
Now, total volume of gas is the beater will Remains constant.

\mathrm{Fern \: n \propto \frac{P}{T}}
therefore ,
        \mathrm{ \frac{n_{1}}{n_{2}}=\frac{P_{1}}{P_{2}} \times \frac{T_{2}}{T_{1}}}
       \mathrm{\frac{n_{1}}{n_{2}}=\frac{2}{1} \times \frac{546}{273}=4}

Since, the final male at. oxygen un the beaker is one - fourth ot the instal Amount \mathrm{25\% } at the the initial Amount.
Therefore \mathrm{M=2, n=5 }

Posted by

qnaprep

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks