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Unpolarised light is is incident from air on a plane surface of a material of refractive index \mu. At a particular angle of incidence 'i', it is found that the reflected and refracted rays are perpendicular to each other. Which of the following options is correct for this situation ?

  • Option 1)

    i = sin^{-1}\left (\frac{1}{\mu} \right )

  • Option 2)

    Reflected light is polarised with its electric vector perpendicular to the plane of incidence

  • Option 3)

    Reflected light is polarised with its electric vector parallel to the plane of incidence

  • Option 4)

    i = tan^{-1}\left (\frac{1}{\mu} \right )

 

Answers (1)

best_answer

As we have learned

Relation between angle of incidence and angle of refaction -

mu _{1}sin i= mu _{2}sin r
 

- wherein

mu _{1}= refractive index of medium of incidence.

mu _{2}=  refractive index of medium where rays is refracted.

i= angle of incidence.

r= angle of refraction.

 

 Apply snells law 

\sin i / \sin r= \mu \rightarrow (1)

also i+r = 90 \degree

\Rightarrow r= 90-i

\Rightarrow \frac{\sin i}{\sin (90-i)}=\mu

or \tan i =\mu

i = \tan ^{-1 }\mu

also reflected light is polarized with its electric field perpendicular to plane of incidence

 

 

 

 


Option 1)

i = sin^{-1}\left (\frac{1}{\mu} \right )

This is incorrect

Option 2)

Reflected light is polarised with its electric vector perpendicular to the plane of incidence

This is incorrect

Option 3)

Reflected light is polarised with its electric vector parallel to the plane of incidence

This is incorrect

Option 4)

i = tan^{-1}\left (\frac{1}{\mu} \right )

This is correct

Posted by

prateek

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