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The Ksp of Ag2CrO4, AgCl, AgBr and AgI are respectively, 1.1 x 10-12, 1.8 x 10-10, 5.0 x 10-13, 8.3 x 10-17. Which one of the following salts will precipitate last if AgNO3 solution is added to the solution containing equal moles of NaCl, NaBr, NaI and Na2CrO4 ?

  • Option 1)

    AgBr

  • Option 2)

    Ag2CrO4

  • Option 3)

    AgI

  • Option 4)

    AgCI

 

Answers (1)

best_answer

 As we discussed @9363 Let us calculate the solability of each salt

Ag_{2}C_{r}\rightarrow 2A_{g}^{+}+C_{r}O_{4}^{2}

1                     0             0

1-s                2s           s           

K_{sp}=\frac{\left ( 2s \right )^{2}s}{1-s}, s< < 1

=1.1\times 10^{-12}=4s^{3}

=s=6.5\times 10^{-5}

A_{g}C_{l}\rightarrow Ag^{+}+Cl^{-}

                s              s

1.8\times 10^{-10}=s^{2}

=s=1.34\times 10^{-5}

silmilarly s for A_{g}B_{r} and A_{g}  1 is 7.1\times 10^{-7} and 9\times 10^{-9} respectively since solubility of Ag_{2}C_{r}O_{4} is lighest, s_{a} it will perticipate lost.


Option 1)

AgBr

Incorrect option

Option 2)

Ag2CrO4

Correct option

Option 3)

AgI

Incorrect option

Option 4)

AgCI

Incorrect option

Posted by

prateek

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