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  • Please help! Two parallel metal plates having charges +Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will

Two parallel metal plates having charges +Q and -Q face each other at a certain distance between them. If the plates are now dipped in kerosene oil tank, the electric field between the plates will

  • Option 1)

    remain same

  • Option 2)

    become zero

  • Option 3)

    increase

  • Option 4)

    decrease

 

Answers (1)

best_answer

 

If K filled between the plates -

{C}'=K\frac{\epsilon _{0}A}{d}={C}'=Ck

C\propto A

C\propto\frac{1}{d}

 

    since Q remains constant. capacitance increase {C}'=K.C

\Rightarrow - wherein optical difference  V=\frac{Q}{C}   decreases

\Rightarrow electric field  E =\frac{v}{d} also differences. 

 


Option 1)

remain same

Incorrect

Option 2)

become zero

Incorrect

Option 3)

increase

Incorrect

Option 4)

decrease

Correct

Posted by

Plabita

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