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Pressure versus temperature graph of an ideal gas at constant volume  V  is shown by the straight line A. Now, mass of the gas is doubled and volume is halved then the corresponding pressure versus temperature graph will be shown by the line.

Option: 1

A


Option: 2

B


Option: 3

C


Option: 4

None of these


Answers (1)

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P=\frac{\mu R T}{V}=\frac{m R T}{M V} \quad\left[\mu=\frac{m}{M}\right]

So at constant volume pressure versus temperature graph is a straight line passing through origin with slope  \frac{m P}{m V}. As the mass is doubled and volume is halved slope becomes  four times. Therefore, pressure versus temperature graph will be shown by the line B.

Posted by

seema garhwal

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