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  • Solve! Following solutions were prepared by mixing different volumes of NaOH and HCI of different concentrations :a. 60 mL —M/10 HC1 + 40 mL —M/10 NaOHb. 55 mL M/10 HCl + 45 mL M/10 NaOHc. 75 mL M/5 HCl + 25 mL M/5 NaOHd. 100 mI—M/1

Following solutions were prepared by mixing different volumes of NaOH and HCI of different concentrations :
a.    60 mL —M/10 HC1 + 40 mL —M/10 NaOH
b.    55 mL M/10 HCl + 45 mL M/10 NaOH
c.    75 mL M/5 HCl + 25 mL M/5 NaOH
d.    100 mI—M/10 HCl + 100 mL —M/10 NaOH

pH of which one of them will be equal to 1 ?

 

  • Option 1)

    d

  • Option 2)

    a

  • Option 3)

    b

  • Option 4)

    c

 

Answers (1)

As we learnt that

The p(H) scale -

Hydronium ion concentration in molarity is more conveniently expressed on a logarithmic scale known as p(H) scale.

- wherein

The p(H) of a solution is defined as negative logarithm to base 10 of the activity of hydrogen ion

P(H)=-log[H^{+}]

 

 As N1V1 > N2V2 so acid left at the end of reaction

N_{mixture} = [H]^{+} =\frac{N_{1}V_{1} - N_{2}V_{2}}{V_{1} + V_{2}} = \frac{\frac{1}{5}X75 - \frac{1}{5}X25 }{75+25} = \frac{1}{10} = 10^{-1}

pH = -log10^{-1} = 1

 

 


Option 1)

d

This is incorrect.

Option 2)

a

This is incorrect.

Option 3)

b

This is incorrect.

Option 4)

c

This is correct.

Posted by

Vakul

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