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The x and y coordinates of the particle at any time are x = 5t - 2t2 and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is

  • Option 1)

    0

  • Option 2)

    5m /s2

  • Option 3)

    -4m /s2

  • Option 4)

    -8m /s2

 

Answers (2)

best_answer

As we learned in concept

Introduction to Differentiation -

frac{d}{dx}left ( x^{n} 
ight )={n} x^{n-1}
 

- wherein

frac{d}{dx}left ( x^{5} 
ight )=left ( n=5 
ight )

Rightarrow {n}x^{n-1}

Rightarrow {5}x^{5-1}

Rightarrow {5}x^{4}

 

 X=5t-2t^{2}                    y=10t
\frac{dx}{dt}=5-4t             \frac{dx}{dt}=10

Vx=5-4t                   vy=10

ax=-4                      ay=0

acc^{n} of particle\: at\: t=2 is =-4m/s^{2}


Option 1)

0

This option is incorrect

Option 2)

5m /s2

This option is incorrect

Option 3)

-4m /s2

This option is correct

Option 4)

-8m /s2

This option is incorrect

Posted by

Aadil

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Answer is 3rd option

Posted by

Umang khetan

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