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  • Stuck here, help me understand: - Gravitation - NEET

A particle of mass M is situated at the centre of a spherical shell of same mass and radius a. The gravitational potential at a point situated at \frac{a}{2} distance frim the centre, will be:

  • Option 1)

    \frac {-3GM}{a}

  • Option 2)

    \frac{-2GM}{a}

  • Option 3)

    \frac{-GM}{a}

  • Option 4)

    \frac{-4GM}{a}

 

Answers (1)

best_answer

As we learnt

Potential due to Uniform Ring -

r= distance from ring

a ightarrow radius of Ring

V ightarrow Potential 

 

- wherein

At a point on its Axis 

V=-frac{GM}{sqrt{a^{2}+r^{2}}}

At the centre 

V=-frac{GM}{a}

 V_{p}=N_{spenual shell}+N_{particle}

\frac{Gm}{a}+\frac{Gm}{\frac{a}{2}}=\frac{3Gm}{a}


Option 1)

\frac {-3GM}{a}

Correct Optino

Option 2)

\frac{-2GM}{a}

Incorrect Option

Option 3)

\frac{-GM}{a}

Incorrect Option

Option 4)

\frac{-4GM}{a}

Incorrect Option

Posted by

divya.saini

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