The sum of coordination number and oxidation number of the metal M in the complex (where is ethyenediamine) is:
9
6
7
8
As we learned in concept
Types of Ligands on the basis of Connectivity -
(i) Unidentate - ligand is bound to metal ion through a single donor atom.
eg:
(ii) Bidentate : when ligand can bind through two donor atoms
eg:
(iii) Polydentate - when ligand bind to two or more donor atoms
(iv) Hexadentate - type of polydentate having six donor atoms
(v) Ambidentate- which can ligate through two different atoms at a time
eg. &
- wherein
All ambidentate ligands are monodentate but all monodentate ligands are not ambidentate
has 3 bidentate ligands which can lead with 2 sites simultaneously. So, the coordination number is 2+2 = 6.
has negative charge of 2. Add that the negative charge on Cl and total negative charge lucomes. The actral atom must have +3 charge to netralize the complex.
therefore, O.N = +3
therfore, ON + CN = 3+6 = 9
therefore, solution is 1
Option 1)
9
correct
Option 2)
6
incorrect
Option 3)
7
incorrect
Option 4)
8
incorrect