Force F on a practicle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12m is
18 J
21 J
26 J
13 J
As we learnt in
Definition of work by constant force -
w =
- wherein
The scalar product of the force vector () and the displacement vector ()
Work done = Area under (f.d) graph = Area of rectangle ABCD + Area of triangle DCE
Option 1)
18 J
This solution is incorrect
Option 2)
21 J
This solution is incorrect
Option 3)
26 J
This solution is incorrect
Option 4)
13 J
This solution is correct