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Force F on a practicle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12m is

  • Option 1)

    18 J

  • Option 2)

    21 J

  • Option 3)

    26 J

  • Option 4)

    13 J

 

Answers (1)

As we learnt in

Definition of work by constant force -

w = underset{F}{
ightarrow}.underset{S}{
ightarrow}

- wherein

The scalar product of the force vector (underset{F}{
ightarrow}) and the displacement vector (underset{S}{
ightarrow})

 Work done = Area under (f.d) graph = Area of rectangle ABCD +  Area of triangle DCE

= 2\times (7-3)+\frac{1}{2}\times 2(12-7)= 8+5 = 13 J


Option 1)

18 J

This solution is incorrect

Option 2)

21 J

This solution is incorrect

Option 3)

26 J

This solution is incorrect

Option 4)

13 J

This solution is correct

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subam

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