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The activation energy of a reaction can be determined from the slope of which of the following graphs?

Option: 1

\ln K vs\: \: T


Option: 2

\frac{\ln K}{T}\: \: vs\: \: T


Option: 3

\ln K\: \: vs\: \: \frac{1}{T}


Option: 4

\frac{T}{\ln K}\: \: vs\: \: \frac{1}{T}


Answers (1)

best_answer

Arrhenius Equation - Arrhenius gave the quantitative dependence of rate constant on temperature by the Arrhenius equation.

k = A e^{-E_{a}/RT}

In K=InA-\frac{E_{a}}{RT}

K = Rate constant

 According to Arrhenius's equation

K=A.e^{\frac{-Ea}{RT}}

=> lnK=lnA-\frac{E_a}{RT}

Hence if lnK is plotted against  \frac{1}{T}, slope of the line will be \frac{-Ea}{R}

The correct answer is option 3. 

Posted by

SANGALDEEP SINGH

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