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  • The angle of a prism is 'A'. One of its reflecting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface returns back through the same path after sufferi

The angle of a prism is 'A'. One of its reflecting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface returns back through the same path after suffering reflection at the silvered surface. The refractive index \mu, of the prism is:

Option: 1

2\sin A


Option: 2

2\cos A


Option: 3

\frac{1}{2}\cos A


Option: 4

\tan A


Answers (1)

best_answer

To retrace its path light rays should fall normally on the reflecting surface. So
r2=0 .

$\Rightarrow r_{1}=A-r_{2} \Rightarrow r_{1}=A$
Now applying snell rule between incident ray and refracted ray.


$(1) \sin (2 A)=n \sin (A) \\ \Rightarrow 2 \sin A \cos A=n \sin A$ $\Rightarrow n=2 \cos A$

Posted by

Rishabh

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