Get Answers to all your Questions

header-bg qa

The azeotropic mixture of acetone and methanol boils at 55.2^{\circ}C.. When this mixture is distilled, what can be obtained?

 

Option: 1

Pure acetone
 


Option: 2

Pure methanol
 


Option: 3

A solution with higher concentration of acetone

 


Option: 4

A solution with higher concentration of methanol


Answers (1)

best_answer

When an azeotropic mixture of acetone and methanol is distilled, it is not possible to obtain pure acetone or pure methanol through simple distillation. However, it is possible to obtain a solution that has a higher concentration of acetone or methanol than the original mixture.

This is because an azeotropic mixture has a constant boiling point and a constant composition in both the liquid and vapour phases. Therefore, when the mixture is distilled, the vapour that is produced has the same composition as the liquid being distilled. As a result, when the vapour is condensed, it forms a liquid that has the same composition as the original mixture.

However, by using a different distillation technique such as azeotropic distillation or extractive distillation, it is possible to break the azeotrope and obtain a solution with a higher concentration of acetone or methanol. Therefore, option C is the correct answer.

Posted by

mansi

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks