Get Answers to all your Questions

header-bg qa

The compressibility factor for \small N_2 at 223 K and 81.06 MPa is 1.95 and at 373 K and 20.265 MPa, it is 1.10. A certain mass of occupies a volume of 1 \small dm^3 at 223 K and 81.06 MPa. Calculate the volume (in dm3) occupies by the same quantity of \small N_2 at 373 K and 20.265 MPa.

(Response should be till 3 decimal points. like 56.789)

Option: 1

3.774


Option: 2

37.74


Option: 3

4.65


Option: 4

3.45


Answers (1)

best_answer

For first conditions, we have:
T = 223 K, P = 81.06 MPa,

Z = 1.95 and V = 1 dm^3 or cm^3
Thus, from compressibility factor equation, we have:

\\\mathrm{Z\:=\: \frac{PV}{nRT}}\\\\\mathrm{n\: =\: \frac{81.06\: x\:10^{3}}{1.95\: x\: 8.314\: x\: 223}\: =\: 22.42\: moles}

For second conditions, we have:
T = 373 K, P = 20.26 MPa, Z = 1.10 and n = 22.42 moles
Thus, from the compressibility factor equation, we have:

\\\mathrm{Z\:=\: \frac{PV}{nRT}}\\\\\mathrm{V\: =\: \frac{1.10\: x\:22.42 \times 8.314 \times 373}{20.625}\: =\: 3774cm^3\: or\: \: 3.774\: dm^3}

 

 

Posted by

Kuldeep Maurya

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks