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The dimension of quantity \frac{1}{2} \frac{B^2}{\mu_0}

Option: 1

ML^2T^{-2}A^{-2}


Option: 2

ML^2T^{-2}A^{-1}


Option: 3

ML^2T^{-2}A


Option: 4

ML^{-1}T^{-2}


Answers (1)

best_answer

As we have learned

Energy Density( u) -

u=\frac{U}{V}= \frac{B^{2}}{2\mu _{0}}

 

- wherein

\frac{U}{V}=Energy stored per unit volume

 

 Enegy density = \frac{1}{2} \frac{B^2}{\mu _0}

Energy density = \frac{Energy }{volume }

  =       \frac{ML^2T^{-2} }{L^3 }

Dimension = ML^{-1}T^{-2}

 

 

 

Posted by

Rishi

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