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  • The energy emitted per second by a black body at 27oC is 10J. If the temperature of the blackbody is increased to 327oC, the energy (in Joule) emitted per second will be<d

The energy emitted per second by a black body at 27oC is 10J. If the temperature of the blackbody is increased to 327oC, the energy (in Joule) emitted per second will be

Option: 1

20


Option: 2

40


Option: 3

80


Option: 4

160


Answers (1)

best_answer

As we have learnt,

 

Temperature of Radiating Body -

Greater the temperature of body.

- wherein

Faster will be cooling

 

 \\E\propto T^4 \\\frac{E_1}{E_2} = \left(\frac{T_2}{T_1} \right )^4 \Rightarrow E_2 = E_1\left(\frac{T_2}{T_1} \right )^4 \\E_2 = 10\times \left(\frac{273+327}{273+27} \right )^4 = 160J

 

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