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The graph which represents the variation of the mean kinetic energy of molecules with temperature C is -

Option: 1


Option: 2


Option: 3


Option: 4


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The mean kinetic energy of the gas molecules,

\begin{aligned} E & =\frac{f}{2} K T \\ & =\frac{f}{2} k(t+213) \\ & =\left(\frac{f}{2} k\right) t+\frac{f}{2} \times 273 k \end{aligned}

Comparing it with the standard equation of a straight line y=mx+c, we get, m=\frac{f k}{2}

and c=\frac{f}{2} 273 k. So the graph between E and t will be a straight line with a positive intercept on E- axis and positive with t- axis.

 

Posted by

Divya Prakash Singh

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