Get Answers to all your Questions

header-bg qa

The heat capacity at constant pressure of a gas varies with temperature as Cp = 9+10T J/(mole-K). What will be the enthalpy of formation (in kJ/mol) when temperature rises to 350 K from 300 K? Given that the enthalpy of formation at 300K is 45 kJ/mol.

Option: 1

208


Option: 2

20


Option: 3

220


Option: 4

45


Answers (1)

best_answer

According to Kirchoff’s equation,

\Delta H_{T_2}=\Delta H_{T_1}+\int_{T_1}^{T_2}CpdT

We have given,

\mathrm{\Delta H_{T_1}=45kJ/mol}

\mathrm{T_1=300K}

\mathrm{T_2=350K}

\mathrm{C_P=(9+10T) \frac{J}{mol-K}}

Putting all these value in the equation we get,

\\\mathrm{\Delta H=45 \times 10^{3}+\int_{300}^{350}(9+10T)dT } \\\\ \Rightarrow\mathrm{ \Delta H=45 \times 10^3 + [9T+5T^2]_{300}^{350} } \\\\\Rightarrow \mathrm{\Delta H=45\times 10^3+[9(350-300)+5 \times(350^2-300^2)] } \\\\\Rightarrow \mathrm{\Delta H=45\times 10^3 + [450+162500] } \\\\ \Rightarrow\mathrm{ \Delta H =208 kJ/mol}

 

 

Posted by

jitender.kumar

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks