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  • The heat of combustion of sucrose (C12H22O11) is 1350 kcal. How much of heat (in kcal) will be liberated when 17.1 g of sucrose is burnt ? (Response shoul

The heat of combustion of sucrose (C12H22O11) is 1350 kcal. How much of heat (in kcal) will be liberated when 17.1 g of sucrose is burnt ?

(Response should be upto only one decimal digit like 78.7 or 0.7).

Option: 1

67.5


Option: 2

13.5


Option: 3

40.5


Option: 4

25.5


Answers (1)

best_answer

Enthalpy of combustion -

The amount of Enthalpy changes when 1 mole of a substance is completely burnt in excess of Oxygen

- wherein

CO+\frac{1}{2}O_{2}\rightarrow CO_{2};\;\;\;\Delta H=-68.3\;kcal

Heat of Reaction -

It is defined as the amount of  Enthalpy change in the reaction for given amount of reaction.

- wherein

C(s)+O_{2}(g)\rightarrow CO_{2}(g);\;\;\;\;\Delta H=-94.3\;kcal 

SOLUTION:

molecular weight of sucrose is 342.3 gm/mol

\\ \textup{heat liberted}=1350 kcal\times\frac{17.1\ gram}{\textup{molecular wt. of sucrose}} \\ \textup{heat liberted}= 67.5 kcal

Posted by

Anam Khan

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