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  • The molar conductance of NaCl ,HCl,and at infinite dilution are 126.45, 426.1

The molar conductance of NaCl ,HCl,and \mathrm{CH_{2}COONa} at infinite dilution are 126.45, 426.16 and \mathrm{91.0 \ S\ cm^{2}mol^{-1}}respectively.The molar conductance of \mathrm{CH_{3}COOH} at infinte dilution is ________.

Choose the right option for your answer:

Option: 1

201.28 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Option: 2

390.71 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1}


Option: 3

\mathrm{698.28\ S\ c m^2 m o l^{-1}}


Option: 4

540.48 \mathrm{~S\ cm}^2 \mathrm{~mol}^{-1}


Answers (1)

best_answer

Given,

\\\mathrm{ \Lambda_m^o, NaCl =126.45 }

\\\mathrm{ \\ \Lambda_m^o, HCl=426.16}

\\\mathrm{ \\ \Lambda_m^o, CH_3COONa =91}

\\\mathrm{ \\ \Lambda_m^o, CH_3COOH =\ ?}

We know from Kohlrausch's Law of independent migration of ions,

\mathrm{\\ \Lambda_m^o, CH_3COOH=\Lambda_m^o, CH_3COONa+ \Lambda_m^o, HCl - \Lambda_m^o, NaCl }

\mathrm{ \Lambda_m^o, CH_3COOH= 91 + 426.16 - 126.45 = 390.71}

Option 2 is correct.

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Nehul

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