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  • The network shown in figure is part of a complete circuit. If at a certain instant the current (I) is 5A, and is decreasing at a rate of <img alt="\mathrm{10^3 \mathrm{~A} / \mathrm{s} \text { then

The network shown in figure is part of a complete circuit. If at a certain instant the current (I) is 5A, and is decreasing at a rate of \mathrm{10^3 \mathrm{~A} / \mathrm{s} \text { then } \mathrm{V}_{\mathrm{B}}-\mathrm{V}_{\mathrm{A}}=}

Option: 1

15V


Option: 2

20V


Option: 3

25V


Option: 4

30V


Answers (1)

best_answer

\mathrm{\begin{array}{ll} V_B+e-15+I \times 1=V_A & \Rightarrow \quad V_B-V_A=15-e-1 \\ \text { Here, } \mathrm{I}=5 \mathrm{~A}, & e=\frac{d \varphi}{d t}=L\left[\frac{-d I}{d t}\right]=-5 \times 10^{-3} \times 10^3=-5 V \\ \mathrm{~V}_{\mathrm{B}}-\mathrm{V}_{\mathrm{A}}=15 \mathrm{~V} & \end{array}}

Posted by

Devendra Khairwa

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