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  • The orbital angular momentum of a p - electron is given as:Option: 1 <img alt="\sqrt 3 \frac{h}{{2\pi}}" src="https://entrancecorner.oncodecogs.com/g

The orbital angular momentum of a p - electron is given as:

Option: 1

\sqrt 3 \frac{h}{{2\pi}}


Option: 2

\sqrt{\frac{3}{2}}\frac{h}{\pi}


Option: 3

\sqrt 6\frac{h}{{2\pi}}


Option: 4

\frac{h}{{\sqrt 2\pi}}


Answers (1)

Orbital angular momentum (m) \mathrm{=\sqrt{l(l+1)}\frac{h}{2 \pi}}

For p electron, the value of azimuthal quantum numbers (l) = 1

Thus,

\mathrm{m=\sqrt{l\times (l+1)}\frac{h}{2\pi}=\frac{\sqrt{2}}{2\pi}}

\mathrm{m = \frac{h}{\sqrt{2}\pi}}

Therefore, Option(4) is correct.

Posted by

Ramraj Saini

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