The pressure exerted by 1 mole of at 273K is 34.98 atm assuming that the volume occupied by
molecules is negligible. The value of Van der Waals constant (in dm6 atm mole-2) for attraction of
gas is:
3.59
3.45
2.76
4.23
As the volume occupied by the molecules of is negligible, thus the value of b is negligible.
Thus the Van der Waals equation is given as follows:
Since V can have only one value, thus discriminant must be zero.