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The reaction X\rightarrow Y is an exothermic reaction.Activation energy of the reaction for X into Y is 150 kJ mol^{-1} .  Enthalpy of reaction is 135 kJ mol^{-1}. The activation energy for the reverse reaction, Y\rightarrow X will be :

Option: 1

280 kJ mol^{-1}


Option: 2

285 kJ mol^{-1}


Option: 3

270 kJ mol^{-1}


Option: 4

15 kJ mol^{-1}


Answers (1)

A potential energy diagram for a reaction that releases energy is:
For an exothermic reaction:

\begin{array}{l} \Delta_{r} H^{\circ}=\left(E_{a}\right)_{r}-\left(E_{a}\right)_{f} \\ \text { Hence, }\left(E_{a}\right)_{r}=\Delta_{r} H^{\circ}+\left(E_{a}\right)_{f} \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\left(135 K J m o l^{-1}\right)+\left(150 K J m o l^{-1}\right) \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =285 K J m o l^{-1} \end{array}

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Kshitij

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