Get Answers to all your Questions

header-bg qa

The solubility order for alkali metal fluoride in water is : 

Option: 1

LiF<RbF<KF<NaF


Option: 2

RbF<KF<NaF<LiF


Option: 3

LiF>NaF>KF>RbF


Option: 4

LiF<NaF<KF<RbF


Answers (1)

best_answer

LiI > NaI > KI > RbI > Cal (solubility)
\text{Lattice energy }\alpha \ \frac{1}{r_{-} + r_{+}}
Since r> r+ ? the sum will not change too much as r+? increases. As a result, the lattice energy will not change significantly as r+? increases. Thus decreases in lattice energy are not as fast as decreases in hydration energy. Thus, more decreases in hydration energy result in decrease insolubility. Thus, solubility decreases as 
LiI > NaI > KI > RbI > Cal
With a small anion as (F-) the lattice energy decreases more rapidly along with a series of salts with increasing cation size and thus solubility increases.
LiF < NaF < KF < RbF < CsF

Posted by

Gaurav

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks