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  • The standard enthalpy of formation of NH3 is -46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is -436 kJ/mol and that of N2 is -712 kJ/mol, the avera

The standard enthalpy of formation of NH3 is -46.0 kJ/mol. If the enthalpy of formation of H2 from its atoms is -436 kJ/mol and that of N2 is -712 kJ/mol, the average bond enthalpy (in kJ/mol) of N-H bond in NH3 is :

Option: 1

-1102


Option: 2

-964


Option: 3

352


Option: 4

1056


Answers (1)

best_answer

 N_{2}+3H_{2}\rightarrow 2NH_{3}

Let x be the bond enthalpy of N-H bond then

\mathrm{\Delta H_{f}= \sum bond \: energies \: of \: products -\sum bonds \: energies \: of \: reactants}

          2\times \left ( -46 \right )=712+3\times (436)-6x

          -92=220-6x\Rightarrow 6x=220+92

         6x=2112\Rightarrow x=+352KJ/mol

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