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  • The two ends of a metal rod are maintained at temperatures 100°C and 110°C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and

The two ends of a metal rod are maintained at temperatures 100°C and 110°C. The rate of heat flow in the rod is found to be 4.0 J/s. If the ends are maintained at temperatures 200°C and 210°C, the rate of heat flow will be:

Option: 1

8.0 J/s


Option: 2

4.0 J/s


Option: 3

44.0 J/s


Option: 4

16.8 J/s


Answers (1)

best_answer

 

Thermal Conductivity -

Q=frac{KA( heta_{1}- heta_{2})t}{l}

K = thermal conductivity

- wherein

 

 Rate of flow of heat =\frac{KA\Delta \Theta }{L}

since rate of flow remain same if temperature difference is same.

Posted by

Ritika Harsh

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