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  • The viscous force acting on a body falling under gravity in a viscous fluid will be Option: 1 <img alt="\frac{6\pi \vartheta }{\eta r}" src="/la

The viscous force acting on a body falling under gravity in a viscous fluid will be 

Option: 1

\frac{6\pi \vartheta }{\eta r}

 

 

 


Option: 2

\frac{6\pi \eta r }{\vartheta }


Option: 3

6\pi \eta r\vartheta


Option: 4

\frac{r\vartheta }{6\pi \eta }


Answers (1)

best_answer

As we learned 

 

Stoke's law -

The magnitude of the viscous force depends on shape/size ,velocity and viscosity of liquid.

- wherein

 

 Viscous force F= 6\pi \eta rv

\eta =coefficient\: of\: viscosity

r=radius\: of\: body

v=velocity\: of\: spherical\: body

 

 

Posted by

manish

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