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  • The work done in turning a magnet of magnetic moment M by an angle of   from the meridian, is n

The work done in turning a magnet of magnetic moment M by an angle of 90^{\circ}  from the meridian, is n times the corresponding work done to turn it through an angle of 60^{\circ}. The value of n is given by

Option: 1

2


Option: 2

1


Option: 3

0.5


Option: 4

0.25


Answers (1)

best_answer

Magnetic moment =M; Initial angle through which magnet is turned \left(\theta_1\right)=90^{\circ} and final angle through which magnet is turned \left(\theta_2\right)=60^{\circ} . Work done in turning the magnet through  \mathrm{ 90^{\circ}\left(W_1\right)=\mathrm{MB}\left(\cos 0^{\circ}-\cos 90^{\circ}\right)}

\mathrm{ =M B(1-0)=M B . \\ .}

\mathrm{ \text { Similarly, } W_2=M B\left(\cos 0^{\circ}-\cos 60^{\circ}\right) \\ .}

\mathrm{ =\mathrm{M}\left(1-\frac{1}{2}\right)=\frac{\mathrm{MB}}{2} \\ .}

\mathrm{ \therefore W_1=2 W_2 \text { or } n=2 .}
 

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Kuldeep Maurya

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