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There is a 1 \mathrm{~mm} thick layer of water between a plate of area 100 \mathrm{~cm}^{2} and another very big plate. The coefficient of viscosity of water is 0.01 poise. Then the force required to move the smaller plate with a velocity of 10 \mathrm{~cm} / \mathrm{sec} with respect to the larger plate is:

Option: 1

10 dyne
 


Option: 2

100 dyne
 


Option: 3

1000 dyne
 


Option: 4

10,000 dyne


Answers (1)

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\mathrm{\begin{aligned} & F=\eta A \frac{d v}{d z} \\ & =0.01 \times 100 \times \frac{10}{0.1} \\ & =100 \text { dyne. } \end{aligned}}

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Ritika Jonwal

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