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An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and 3 cm deep when viewed from the opposite face. The thickness (in cm) of the slab is

Answers (1)

@Krupa

As we learnt in

Relation between real depth and apparent depth -

\frac{n_{i}}{d}= \frac{n_{r}}{d{}'}

 

- wherein

n_{i} = Refractive index of medium of incident.

n_{r} = Refractive index of medium of refraction.

d = distance of object.

d{}' = apparent  depth

 

 

Apparent depth = 5cm  from one side 

\therefore Real depth=1.5 \times 5=7.5 cm 

apparent depth = 3cm from other side 

\therefore Real depth from other side =3 \times 1.5cm = 4.5 cm

\therefore Thickness of slab = 7.5cm + 4.5cm = 12cm

12. An air bubble in a glass slab with refractive index 1.5 (near normal incidence) is 5 cm deep when viewed from one surface and  3 cm deep 
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Abhishek Sahu

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