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Three compounds are formed from X  & Y, A fixed mass of X combines with different mass of Y which is in the ratio of 1: 3: 5 in compounds A, B & C. Calculate the parts by mass of Y which will combine with 8 parts by mass of X in compound C. It is given that 16 parts by mass of x combines with 42 parts by mass of Y in b and atomic weight of  X & Y is 18 & 16, respectively.

Option: 1

15 parts by mass of Y 


Option: 2

30 parts by mass of Y 


Option: 3

35 parts by mass of Y 


Option: 4

50 parts by mass of Y


Answers (1)

best_answer

Mass ratio of Y in compound A, B & C=1: 3: 5 in B, 16 parts of X combines with 42 parts of Y. In C, 8 parts of X reacts with m parts of Y.

Accordingly,

\mathrm{\text { B } \quad 42 / 16 \quad 3}

\mathrm{\text { C } \quad \mathrm{m} / \mathrm{8}\; \; \; \; \; \; 5}

\mathrm{\frac{\frac{42}{16}}{\frac{m}{8}}=\frac{3}{5}}

\mathrm{m=\frac{42 \times 8 \times 5}{16 \times 3}=35}

Posted by

Anam Khan

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