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Screenshot_20190110-230433.png
three particles of masses 1kg, 2kgand 3kg are subjected to forces of (3i-2j+2k)N, (-i+2j-k)N and (i+j+k)N respectively. What will be the magnitude of acceleration of centre of mass of the system?
Answers (1)
a(cm) = ( m1a1 + m2a2 + m3a3)/(m1 + m2 + m3)
a=(3i-2j+2k-i+2j-k+i+j+k)/(3+2+1)=
a=(3i+j+2k)/6,
now magnitude of accelaration
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