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  • Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on the screen. Phase difference between the beams is <img alt="\frac{\pi}{2}" src="https://entrancecorner.oncod

Two beams of light having intensities I and 4 I interfere to produce a fringe pattern on the screen. Phase difference between the beams is \frac{\pi}{2}  at point a and \pi at point B. Difference of intensities at A and B is

Option: 1

3 I


Option: 2

4 I


Option: 3

5 I


Option: 4

6 I


Answers (1)

best_answer

\mathrm{\text { Given } I_{1}=I_{1} I_{2}=4 I ; \quad \theta_{1}=\frac{\pi}{2} \text { and } \theta_{2}=\pi}
\mathrm{I_{A}=I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \theta_{1} \\ }
\mathrm{ I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \frac{\pi}{2}=I_{1}+I_{2}=5 \mathrm{I} }
\mathrm{ I_{B}=I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \theta 2 }
\mathrm{=I_{1}+I_{2}+2 \sqrt{I_{1} I_{2}} \cos \pi=I }

\mathrm{ \therefore I_{A}-I_{B}=5 I-I=4 I }

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shivangi.shekhar

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