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Two cars  A  and  B  are moving away from each other in opposite direction. Both the cars are moving with a speed of  25 m/s with respect to the ground. If an observer in car  A  detecter a frequency 1500 Hz of the sound coming from car  B, what is the natural frequency of the sound source in car B? (speed of sound in air 332 m/s)


 

Option: 1

1744.3 Hz


Option: 2

1533.2 Hz


Option: 3

1433.7 Hz


Option: 4

1623 Hz


Answers (1)

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V _ { sound }=332 \mathrm{~m} / \mathrm{s} \\

n=n_0\left[\frac{V_{\text {sound }}-V_0}{V_{\text {Sound }}+V_s}\right] \\

1500=n_0\left[\frac{332-25}{332+25}\right] \\

1500=n_0\left[\frac{307}{357}\right] \\

{ n_0 }=\frac{1500}{\frac{307}{357}}

n_0=\frac{1500 \times 357}{307}=\frac{535500}{307} \\

{ n_0 }=1744.3 \text { Hz } \\

Posted by

Kuldeep Maurya

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