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Two circular discs having radius \mathrm{R} and mass density \mathrm{\sigma \: and \, 2 \sigma} respectively are placed as shown in figure. The find out the position of COM will be -


 

Option: 1

\mathrm{\frac{4 R}{3}}
 


Option: 2

\mathrm{\frac{2 R}{3}}
 


Option: 3

\mathrm{\frac{4 R}{5}}
 


Option: 4

\mathrm{\frac{2 R}{30}}


Answers (1)

best_answer

Due to symmetry the COM of Disc A lie at point \mathrm{o} and COM of disc B lie at point \mathrm{O'}.so we realize above problem in a following way.

COM Due to both the disc lie at point C (assume) ,having distance X from \mathrm{m_{A}}

\mathrm{x=\frac{m_B(2 R)}{m_A+m_B}, x =\frac{2 \sigma \pi R^2(2 R)}{\sigma\left(\pi R^2+2 \pi R^2\right)} }

                              \mathrm{x =\frac{4 R}{3} }

Hence option 1 is correct.


 

Posted by

Ritika Kankaria

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