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Two communicating vessels contain mercury. The diameter of one vessel is n times larger than the diameter of the other. A column of water of height h is poured into the left vessel. The mercury level will rise in the right-hand vessel (s= relative density of mercury and \mathrm{ \rho} = density of water) by

Option: 1

\mathrm{\frac{n^2 h}{(n+1)^2 s}}


Option: 2

\mathrm{\frac{h}{\left(n^2+1\right) s}}


Option: 3

\mathrm{\frac{h}{(n+1)^2 s}}


Option: 4

\mathrm{\frac{h}{n^2 s}}


Answers (1)

best_answer

Area ratio \mathrm{=1: \mathrm{n}^2}
Height h in water \mathrm{\Rightarrow \frac{\mathrm{h}}{\mathrm{s}}} in mercury

If all water correspond to mercury

Extra height \mathrm{\Rightarrow \frac{h / s}{n^2+1}}

Posted by

Rishabh

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