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Two elements X and Y have atomic weights of 14 and 16. They form a series of compounds A,B,C,D and E in which for the same amount of element X, the element Y is present in the ratio 1:2:3:4:5. If the compound A has 28 parts byweight of  X and 16 parts by weight of Y , then the compound of C will have 28 parts weight of X and

Option: 1

32 parts by weight of Y

Option: 2

48 parts by weight of Y

Option: 3

64 parts by weight of Y

Option: 4

80 parts by weight of Y

Answers (1)



For the same weight of element X, ratio of weights of Y in compounds A and C= 1 : 3

Thus, in the compound C , the weight of Y present is 16 \times 3 = 48 \ g

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