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Two gases occupy two containers A and B of the gas in A, of volume 0.10 \mathrm{~m}^{3}, exist pressure of 1.40 \mathrm{\mu Pa}, and that in $B$ of volume 0.15 \mathrm{~m}^{3} exerts a pressure 0.7 \mathrm{\mu Pa}. The two containers are united by a tube of negligible volume and the gases are allowed to intermingle. Then if the temperature remains constant, the final pressure in the container will be (in MPG) -

Option: 1

0.70


Option: 2

0.98


Option: 3

1.40


Option: 4

2.10


Answers (1)

best_answer

As the quantity of gas remains constant -

\begin{aligned} \mu_{A}+\mu_{B} & =\mu \\ \frac{P_{A} P_{A}}{R T}+\frac{P_{B} V_{B}}{R T} & =\frac{P\left(V_{A}+V_{B}\right)}{R T} \\ & \Rightarrow P=\frac{P_{A} V_{A}+P_{B} V_{B}}{V_{A}+V_{B}}=\frac{(1.4 \times 0.1)+(0.7 \times 0.15)}{0.1+0.15} \\ & =0.98 \mathrm{\mu Pa} \end{aligned}
 

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jitender.kumar

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