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Two particles of mass 5kg and 10kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of:
Option: 1  33 cm  
Option: 2 50 cm
Option: 3 67 cm
Option: 4 80 cm

Answers (1)

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\text { The position of } COM \text { from } m _{1} \text { mass is } \frac{ m _{2} r }{\left( m _{1}+ m _{2}\right)}

Here, m1 = 5  kg

r = 1 m

m2 = 10 kg

By putting this value we will get 0.666667 meter

or we can write = 67 cm

Posted by

Deependra Verma

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